In: Statistics and Probability
When a dice is thrown twice, the following possible samples may
arise:
S = {(1,1), (1,2), (1,3), (1,4), (1,5),
(1,6),
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}
The samples favourable to A are:
A = {(1,1), (1,3), (1,5),
(2,2), (2,4), (2,6),
(3,1),(3,3), (3,5),
(4,2), (4,4), (4,6),
(5,1), (5,3), (5,5),
(6,2), (6,4), (6,6)}
Now,
The samples favourable to B are:
B = {(1,2), (1,4), (1,6),
(2,2), (2,4) (2,6),
(3,2), (3,4), (3,6),
(4,2), (4,4), (4,6),
(5,2), (5,4), (5,6),
(6,2), (6,4), (6,6)}
Now,
The samples favourable to both A and B are:
=
{(2,2), (2,4) (2,6),
(4,2), (4,4), (4,6),
(6,2), (6,4), (6,6)}
Now,
For the events A and B to be
independent, we must have,
R.H.S.
= L.H.S.
Hence, the events are independent using the rule of multiplication of independent events.
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