Total number of six-digit numbers in which only and all the five digits 1, 3, 5, 7, and 9 appear, is

Total number of six-digit numbers in which only and all the five digits 1, 3, 5, 7, and 9 appear, is

(a) 56

(b) (½)(6!)

(c) 6!

(d) (5/2) 6!

Expert Solution

Selecting all 5 digits = ⁵C5 = 1 way

We need to select one more digit to make it a 6 digit number = ⁵C1 = 5 ways

Total number of permutations = 6!/2!

Therefore now we have,

Total numbers = ⁵C5×⁵C1×(6!/2!)

= (5/2) 6!

Hence option d is the answer.

Total number is (5/2)6!

Nikhil Thakur answered 2 years ago

5. Using only the digits of 1, 4, 5, 8, (a) How many three digit numbers...

5. Using only the digits of 1, 4, 5, 8, (a) How many three digit numbers can be formed? (b) How many odd numbers greater than 10 can be formed? (c) How many even number less than 300 can be formed? Repetition is allowed!

In game 77, a 7-digit winning number consisting of the digits 0 to 9 is drawn...

In game 77, a 7-digit winning number consisting of the digits 0 to 9 is drawn one after the other (they put the numbers back in the bag before drawing another number) and their digits are arranged in the order of the draw. What is the probability that the numbers drawn in non-descending sequence, i.e. the number of a drawing is at least as large as the number of the previous drawing? Also calculate this probability for the general case...

Using the digits 2 through 8, find the number of different 5-digit numbers such that: (a)...

Using the digits 2 through 8, find the number of different 5-digit numbers such that: (a) Digits can be used more than once. (b) Digits cannot be repeated, but can come in any order. (c) Digits cannot be repeated and must be written in increasing order. (d) Which of the above counting questions is a combination and which is a permutation? Explain why this makes sense

Using the digits 0 through 8, find the number of different 5-digit numbers such that: a....

Using the digits 0 through 8, find the number of different 5-digit numbers such that: a. Digits can be used more than once. b. Digits cannot be repeated, but can come in any order. c. Digits cannot be repeated and must be written in increasing order. d. Which of the above counting questions is a combination and which is a permutation? Explain why this makes sense.

1. A three-digit number is formed from nine numbers (1, 2, 3, 4, 5, 6, 7,...

1. A three-digit number is formed from nine numbers (1, 2, 3, 4, 5, 6, 7, 8 & 9). No number can be repeated. How many different three-digit numbers are possible if 1 and 2 will not be chosen together? Select one: A. 672 B. 210 C. 462 D. 336 2. In a recent survey conducted by a professor of UM, 200 students were asked whether or not they have a satisfying experience with the e-learning approach adopted by the...

For 3 digits password. a). Find all possible outcomes of 3 digits of 0-9 numbers with...

For 3 digits password. a). Find all possible outcomes of 3 digits of 0-9 numbers with no repetition allowed b). Find all possible outcomes of 3 digits of 0-9 numbers with repeition allowed but no more than two repetition c). Find all possible outcomes of 3 digits of 0-9 for repetition numbers only. d) Find all possible outcomes of 3 digits of 0-9 for repeition numbers only but no more than 2 repetition. e). Find all possible outcomes of 3...

Question

Total number of six-digit numbers in which only and all the five digits 1, 3, 5, 7, and 9 appear, is

Solutions

Expert Solution

Related Solutions