In: Chemistry
Compound A and compound B both have molecular formula C6H12. Both compound produce epoxides when treated with MCPBA. The epoxide resulting from compound A was treated with aqueous acid (H3O+) and the resulting diol has no chirality centers. Propose two possible structures for compound A. The epoxide resulting from compound B was treated with (H3O+) and the resulting diol was a meso compound. Draw the structure of compound B.
The given molecular formula is C6H14
So there is one double bond in the given compounds (A and B) as both are giving epoxides on treatment with m-CPBA.
a) The epoxide resulting from compound A was treated with aqueous acid (H3O+) and the resulting diol has no chirality centers: It means that the compound has no chiral centre (carbon with four different functional groups).
b)The epoxide resulting from compound B was treated with (H3O+) and the resulting diol was a meso compound.