Question

In: Advanced Math

The big jar of nickels and dimes contained $45. If 700 coins were in the jar, how many of each kind were there?

The big jar of nickels and dimes contained $45. If 700 coins were in the jar, how many of each kind were there?

Solutions

Expert Solution

a) X + y = 700. X = nickels, y = dimes b) X × y = 700 c) Subtract y from the right side and the left side of the equation d) X = 700 - y. e) Start with the original equation, again. Subtract X from the right side and the left side of the equation. f) y = 700 - X. g).05(700 -y) + ,10y = 45. h) 35 -.05y + .10y = 45. i) Subtract 35 from the left side and the right side of the equation. j) .05y = 10 k) Divide both sides of the equation by .05. l) y = 200 dimes m) X = 700 - y. n) X = 700 - 200 = 500 nickels.

500

Arjoma Karan answered 2 years ago
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