At t = 0, an electron (mass = 9.11 ×10-31 kg) is released from rest 1.00...

At t = 0, an electron (mass = 9.11 ×10-31 kg) is released from rest 1.00 meter above the center of a charged, circular ring, which has a total charge of –3.00 nC. The diameter of the ring is 2.00 meters and the plane of the ring is oriented horizontally. What are the magnitude and direction of the acceleration of the electron, just after it is released?

Expert Solution

Electric field due to a charged spherical ring at a distance x is given by

Where r is the radius of the ring.

Here the electron is released 1 m above the center of the wire(radius=1 m)

Electric field at the position of the electron is

Force experienced by the electron

Magnitude of this force is

This will cause the electron to accelerate with a value

Both the electron and the ring are negatively charged. Hence the force among them is repulsive. As a result the electron will experience this amount of acceleration away from the center of the ring perpendicular to the diameter.

genius_generous answered 2 years ago

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