In: Statistics and Probability
1. 50 part-time students were asked how many courses they were taking this term. The (incomplete) results are shown below:
# of Courses | Frequency | Relative Frequency | Cumulative Frequency |
1 | 15 | 0.3 | |
2 | 23 | ||
3 |
a. Complete the table.
b. What percent of students take exactly one course? _____%
2. The five number summary of a data set was found to be:
0, 4, 11, 15, 20
An observation is considered an outlier if it is below: _____
An observation is considered an outlier if it is above: _____
3. This data is from a sample. Calculate the mean, standard deviation, and variance.
x | 27 | 38.2 | 28.4 | 45.7 | 20.6 | 20.1 | 23.6 | 42.1 | 11.3 |
---|
Please show the following answers to 2 decimal
places.
Sample Mean = ______
Sample Standard Deviation = ______
Sample Variance = _____ (Please use the standard deviation above
for your calculation.)
Oops - now you discover that the data was actually from a
population! So now you must give the population
standard deviation.
Population Standard Deviation = _____
4. We are going to calculate the mean, median,
and mode for two sets of data. Please show your answer to
one decimal place if necessary.
Here is the first data set.
27 | 88 | 84 | 56 | 49 | 39 | 86 | 33 | 53 | 24 | 53 |
what is the mean (x¯) of this data set? ____
What is the median of this data set? _____
What is the mode of this data set? ____
Here is the second data set.
65 | 89 | 56 | 22 | 30 | 30 | 31 | 95 | 68 | 59 |
What is the mean (¯xx¯) of this data set? ____
What is the median of this data set? ____
What is the mode of this data set? _____
5. E and F are mutually exclusive events. P(E) = 0.91; P(F) = 0.42. Find P(E | F) _____
6. A special deck of cards has 3 blue cards, and 7 orange cards. The blue cards are numbered 1, 2, and 3. The orange cards are numbered 1, 2, 3, 4, 5, 6 and 7. The cards are well shuffled and you randomly draw one card.
B = card drawn is blue
O = card drawn is odd-numbered
a. How many elements are there in the sample space? _____
b. P(B) =____
7. The table summarizes results from pedestrian deaths that were caused by automobile accidents.
Driver Intoxicated? |
Pedestrian Intoxicated? | |
---|---|---|
Yes | No | |
Yes | 56 | 79 |
No | 249 | 592 |
If one of the pedestrian deaths is randomly selected, find the
probability that the pedestrian was intoxicated. (Round your answer
to 4 decimal places.)
Probability = _______
#a. Complete the table.
# of Courses | Frequency | Relative Frequency | Cumulative Frequency |
1 | 15 | 0.3 | 15 |
2 | 23 | 0.46 | 38 |
3 | 12 | 0.24 | 50 |
sum | 50 | 1 |
#Relative frequency=frequency /Total frequency
b. What percent of students take exactly one course?
Ans: percent of students take exactly one course is =(15/50)*100=30
therefore 30 % of students take exactly one course
Ans2. The five number summary of a data set was found to be:
>
x=c(0,4,11,15,20);x
[1] 0 4 11 15 20
> summary(x)
Min. 1st Qu. Median Mean 3rd Qu. Max.
0 4 11 10 15 20
> boxplot(x)$out
numeric(0)
#hence there is no outlier
Ans3:
>
x=c(27,38.2,28.4,45.7,20.6,20.1,23.6,42.1,11.3);x
[1] 27.0 38.2 28.4 45.7 20.6 20.1 23.6 42.1 11.3
> mean(x)
[1] 28.55556
> var(x)
[1] 128.7428
># sd=standard deviation x
> sd=sqrt(var(x));sd
[1]
11.34649
> Sample Mean = 28.55
Sample Standard Deviation = 11.35
Sample Variance =128.7428
#Population Standard Deviation
first we find population variance
population variance=((n-1)\n)*var=(9/8)*128.7428=144.83
Population Standard Deviation =sqrt(144.83)=12.03
#Population Standard Deviation =12.03