In: Chemistry
0.170g of caffeine is dissolved in 10.0mL of water. The caffeine is extracted from the aqueous solution three times with 5.0-mL portions of methylene chloride. Calculate the total amount of caffeine that can be extracted into three portions of methylene chloride. Caffeine has a distribution coefficient of 4.6 between methylene chloride and water.
Please explain throughoutly. This is my first time working with extraction question
Weight of caffeine is W = 0.170 gm.
Volume of water is V= 10 ml
Volume of methylene chloride which extracted caffeine is v= 5ml
No of portions n=3
Distribution co-efficient= 4.6
TOTAL AMOUNT OF CAFFEINE THAT CAN BE UNEXTRACTED IS GIVEN BY
wn= WX[KDxV/(KDxV+v)]n
w3= 0.170[ (4.6x10)/(4.6X10+5)]3
= 0.170[46/46+5]3
= 0.170[46/51]3
=0.170[97336/132651
= 0.170X0.734
=0.125 gms
. AMOUNT OF CAFFEINE UN EXTRACTED IS 0.125 gms.
AMOUNT OF CAFFEINE EXTRACTED = 0.170-0.125
=0.045 gms