Question

In: Statistics and Probability

Experimenter bias refers to the phenomenon that data tends to comes out in the desired direction...

Experimenter bias refers to the phenomenon that data tends to comes out in the desired direction even for the most conscientious experimenters. A social psychologist hypothesizes the opposite phenomenon. The psychologist tells a sample of students that they will be the experimenters in a study, and are then told that all subjects in the study will be given nicotine one hour before solving arithmetic problems; in reality none of the subjects were given nicotine. However, half of the experimenters are told that nicotine will lead to better performance and the other half are told nothing. The experimenters are then asked to score the arithmetic problems from the subjects. Below are the scores they gave. What can be concluded with an α of 0.01?

told
nothing
told
nicotine
12
14
13
8
14
10
20
10
18
15
21
12
17
14
21
24





c) Obtain/compute the appropriate values to make a decision about H0.
(Hint: Make sure to write down the null and alternative hypotheses to help solve the problem.)
critical value = _________ ; test statistic = __________
Decision:Reject H0 or Fail to reject H0

d) If appropriate, compute the CI. If not appropriate, input "na" for both spaces below.
[ _____, ______ ]

e) Compute the corresponding effect size(s) and indicate magnitude(s).
If not appropriate, input and/or select "na" below.
d = ________ ; na trivial effect small effect medium effect large effect
r2 = ________ ;  ---Select--- na trivial effect small effect medium effect large effect

f) Make an interpretation based on the results.

Experimenters that were told nothing gave significantly higher scores than experimenters that expected a good performance.

Experimenters that expected a good performance gave significantly higher scores than experimenters that were told nothing.   

There was no significant score difference between experimenters that expected a good performance and those that were told nothing.

Solutions

Expert Solution

Answer:-

Given That:-

Experimenter bias refers to the phenomenon that data tends to comes out in the desired direction even for the most conscientious experimenters. A social psychologist hypothesizes the opposite phenomenon.

c) Obtain/compute the appropriate values to make a decision about H0.
(Hint: Make sure to write down the null and alternative hypotheses to help solve the problem.)
critical value = _________ ; test statistic = __________
Decision:Reject H0 or Fail to reject H0

Ho : µ1 - µ2 = 0
Ha : µ1-µ2 < 0
  
Level of Significance , α = 0.01
  
Sample #1 ----> sample 1
mean of sample 1,

x̅1= 12.63
standard deviation of sample 1,

s1 = 3.66
size of sample 1,

n1= 8
  
Sample #2 ----> sample 2
mean of sample 2,

x̅2= 17.75
standard deviation of sample 2,

s2 = 4.06
size of sample 2,

n2= 8
  
difference in sample means = x̅1-x̅2

= 12.6250 - 17.8

= -5.13
  
pooled std dev , = 3.8672
std error ,

= 1.9336
  
t-statistic =

= (-5.1250 - 0 ) / 1.93

= -2.65
  
Degree of freedom, DF = n1+n2-2

= 14
t-critical value , t* = -2.6245 (excel function: =t.inv(α,df)
Decision: | t-stat | > | critical value |, so, Reject Ho   

d) If appropriate, compute the CI. If not appropriate, input "na" for both spaces below.
[ _____, ______ ]

Degree of freedom, DF= n1+n2-2

= 14
t-critical value = t α/2 = 2.9768 (excel formula =t.inv(α/2,df)
  
pooled std dev , = 3.8672
  
std error ,

= 1.9336
margin of error, E = t*SE

= 2.9768 * 1.9336

= 5.7560
  
difference of means = x̅1-x̅2

= 12.6250 - 17.750

= -5.1250
confidence interval is   
Interval Lower Limit= (x̅1-x̅2) - E

= -5.1250 - 5.7560

= -10.8810
Interval Upper Limit= (x̅1-x̅2) + E

= -5.1250 + 5.7560

= 0.6310
CI (-10.881 , 0.631)


e) Compute the corresponding effect size(s) and indicate magnitude(s).
If not appropriate, input and/or select "na" below.
d = ________ ; na trivial effect small effect medium effect large effect
r2 = ________ ;  ---Select--- na trivial effect small effect medium effect large effect.

effect size,
cohen's d = |( x̅1-x̅2 )/Sp |

= 1.325
LARGE

r² = d²/(d² + 4) = 0.305
LARGE


f) Make an interpretation based on the results.

Experimenters that expected a good performance gave significantly higher scores than experimenters that were told nothing.   

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