Question

a. Classify each of the compounds as soluble or not soluble:

sodium phosphate_________

copper(II) acetate_________

magnesium iodide

lead hydroxide_________

iron(II) carbonate_________

chromium(III) nitrate

silver sulfide

zinc phosphate ammonium acetate

b. Write the net ionic equation for the precipitation of chromium(III) hydroxide from aqueous solution:

c.Write the net ionic equation for the precipitation of calcium phosphate from aqueous solution:

d. Write the net ionic equation for the precipitation of copper(II) carbonate from aqueous solution:

e. When aqueous solutions of sodium phosphate and nickel(II) nitrate are combined, solid nickel(II) phosphate and a solution ofsodium nitrate are formed. The net ionic equation for this reaction is:

f.When solid Zn metal is put into an aqueous solution of CuSO₄, solid Cu metal and a solution of ZnSO₄ result. Write the net ionic equation for the reaction.

g. When aqueous solutions of potassium acetate and nitric acid are mixed, an aqueous solution of potassium nitrate and acetic acidresults. Write the net ionic equation for the reaction.
Use H⁺ for the hydronium ion, CH₃COOH for acetic acid and CH₃COO^- for the acetate ion.

Answer 1

1A) Sodium phophate soluble in water

B)copper(ii) acetate soluble in alclhol, slight soluble in ether

C) magnesium iodide soluble in ether, alcohol and ammonia

D) lead hydroxide soluble in dilute acid and alkalis; insoluble in acetone and acetic acid

E)  iron(II) carbonate No, it is not soluble. Carbonates are generally insoluble, except when mixed with Group 1 cations and ammonium

F) chromium(III) nitrate solublewater [H2O]: 208 (15°) ethanol [C2H5OH]: soluble

(B) a. chromium (III) chloride and sodium hydroxide

Cr+3 & 3 OH- --> Cr(OH)3 (s)

b. silver nitrate and ammonium carbonate
2Ag+ & (CO3)-2 --> Ag2CO3 (s)

c. copper (II) sulfate and mercury (I) nitrate
(Hg2)+2 & (SO4)-2 --> Hg2SO4 (s)

d. Strontium nitrate and potassium iodide
no

C) A precipitate of calcium phosphate will form

3 CaCl2 (aq) + 2 K3PO4 (aq) = Ca3(PO4)2 (s) + 6 KCl (aq)

3 Ca2+ + 6 Cl- + 6 K+ + 2 PO43- = Ca3(PO4)2 + 6 K+ + 6 Cl-

to get the net ionic cancel the spectator ions

3 Ca2+ + 2 PO43- = Ca3(PO4)2

fZn(s)+SnSO4(aq) gives ZnSO4(aq)+Sn(s)
Zn+2(s)+Sn+2+SO4-2(aq) gives Zn+2+SO4-2(aq)+Sn+2(s0
in this SO4-2 ions are canceled out as they play role of spectator ions
So
Zn+2(s)+Sn+2(aq) gives Zn+2(aq)+Sn+2(s))