In: Statistics and Probability
or a sample group of 25 men subjected to a stress situation, the meannumber of heartbeats per minute was 76, and the standard deviation was 6.
Find the95% confidence interval of the true mean.Write a conclusion for the confidence interval.Round to 3 decimal places.
Solution :
Given that,
= 76
s = 6
n = 25
Degrees of freedom = df = n - 1 = 25 - 1 = 24
At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
t /2,df = t0.025,24 =2.797
Margin of error = E = t/2,df * (s /n)
= 2.797 * (6 / 25)
= 2.48
Margin of error = 2.48
The 95% confidence interval estimate of the population mean is,
- E < < + E
76 - 2.48 < < 76 + 2.48
73.52 < < 78.48
(73.52, 78.48 )