Calculate the pH and pOH of a
0.50 M solution of Acetic Acid. The Ka of HOAc is 1.8
x10-5
[H3O+]/(0.50-0.00095)=1.8x10-5 where did they get the .00095,
its said to take that as the second assumption
[H3O+]=9.4x10-4
[H3O+]/(0.50-0.00094)=1.85x10-5
[H3O+]=9.4x10-4 (this is said to be the third assumption)
Please, please help I really dont understand this, please show
all steps and be as descriptive as possible.