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How many moles of potassium chloride must be added to the solution to completely precipitate 1.18g...

How many moles of potassium chloride must be added to the solution to completely precipitate 1.18g dissolved Ag?

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Expert Solution

Reaction between KCl and Ag take place as given below

Ag(aq) + KCl(aq)     AgCl(s)   + K(aq)

According to reaction 1 mole of Ag react with 1 mole of KCl to form AgCl precipitate

first calculate mole of Ag

molar mass of Ag = 107.8683 gm / mole then 1.18 gm of Ag = 1.18 / 107.8683 = 0.0109392658 mole of Ag

According to reaction 1 mole of Ag react with 1 mole of KCl to form AgCl precipitate then to precipitate 0.0109392658 mole of Ag required KCl = 0.0109392658 mole

queen_honey_blossom answered 2 years ago
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