Question

A)

[Metacritic and Once Upon a Time... in Hollywood] One of the movies that the Metacritic rated was Once Upon a Time... in Hollywood.Based on the data from Metacritic on April 21, 2020, there are n=36 reviews, the sample average score is 67.56, and the sample standard deviation is 9.65.

A 99% confidence interval for the true average score (µ) of Once Upon a Time... in Hollywood is:

	a.	[63.42, 71.70]
	b.	[63.18, 71.94]
	c.	[64.84, 70.28]
	d.	[60.94, 72.18]

B)

A 95% confidence interval for the true average score (µ) of Once Upon a Time... in Hollywood is:

	a.	[64.29, 70.83]
	b.	[64.41, 70.71]
	c.	[63.42, 71.70]
	d.	[66.22, 68.90]

Answer 1

Solution :

Given that,

A

t /2,df = 2.724

Margin of error = E = t/2,df * (s /n)

= 2.724 * (9.65 / 36)

Margin of error = E = 4.38

The 99% confidence interval estimate of4.38 the population mean is,

- E < < + E

67.56 - 4.38 < < 67.56 + 4.38

63.18 < < 71.94

(63.18 , 71.94)

option b. is correct

B

t /2,df = 2.0301

Margin of error = E = t/2,df * (s /n)

= 2.0301 * (9.65 / 36)

Margin of error = E = 3.27

The 95% confidence interval estimate of the population mean is,

- E < < + E

67.56 - 3.27 < < 67.56 + 3.27

64.29 < < 70.83

(64.29 , 70.83)

option a. is correct