Question

In: Statistics and Probability

A tourist agency in Florida claims the mean daily cost of means and lodging for a...

A tourist agency in Florida claims the mean daily cost of means and lodging for a family of four traveling in Florida is $568. You work for a consumer protection advocate and want to test the claim. In a random sample of 50 families of four traveling in Florida, the mean daily cost of means and lodging is $584 and the standard deviation is $25

  1. Do you have enough evidence to reject the agency’s claim?

  1. What type of error is possible based on your conclusion?

  1. What would be a consequence of this type of error in this situation?

Solutions

Expert Solution

Let be the true mean daily cost of meals and lodging for a family of four traveling in Florida. We want to test the claim that the mean daily cost of meals and lodging for a family of four traveling in Florida is $568. That is, we want to test the claim that

The hypotheses we want to test are

We will test the hypotheses at 5% level of significance

We have the following sample information

n=50 is the sample size

is the sample mean daily cost of meals and lodging for a family of four traveling in Florida.

is the sample standard deviation of daily cost of meals and lodging for a family of four traveling in Florida

We do not know the population standard deviation. We will estimate it using the sample

The estimated standard error of mean is

Since the sample size is greater than 30, using the central limit theorem, we can say that the sampling distribution of mean is normal. That is, we will use a 1 sample z test for mean.

The hypothesized value of mean is (from the null hypothesis)

The test statistic is

This is a 2 tailed test. (The alternative hypothesis has "not equal to").

The right tail critical value for is

Using the standard normal tables, we get for z=1.96, P(Z<1.96)=0.975.

The critical values are -1.96 and +1.96

We will reject the null hypothesis if the test statistic is not within the range of critical values.

Here, the test statistic is 4.525 and it is outside the range -1.96 and +1.96. Hence we reject the null hypothesis.

Do you have enough evidence to reject the agency’s claim?

ans: Yes: We have sufficient evidence to reject the agency's claim that the mean daily cost of meals and lodging for a family of four traveling in Florida is $568.

What type of error is possible based on your conclusion?

We have rejected the null hypothesis. That is we have rejected the agency's claim based on the sample evidence.  However, if the agency's claim were true, we would wrongly have rejected a true claim.

If we reject a the null hypothesis which is true, we commit a type I error.

ans: Type I error is possible, based on our conclusion as it is possible that we have rejected a null hypothesis, which is true.

What would be a consequence of this type of error in this situation?

ans: the consequence is, we would wrongly have rejected the true claim by the agency that the mean daily cost of meals and lodging for a family of four traveling in Florida is $568.


Related Solutions

The American Automobile Association claims that the mean nightly lodging rate for a family of four...
The American Automobile Association claims that the mean nightly lodging rate for a family of four traveling on vacation in Florida is $185. A random sample of 6 such families results in the following costs in dollars: 154, 185, 167, 150, 184, 182. At the .05 significance level, is there sufficient evidence that the mean nightly lodging rate for a family of four traveling on vacation in Florida is different than $185? Assume that lodging costs are normally distributed.
A credit reporting agency claims that the mean credit card debt in a town is greater...
A credit reporting agency claims that the mean credit card debt in a town is greater than $3500. A random sample of the credit card debt of 20 residents in that town has a mean credit card debt of $3619 and a standard deviation of $391. At α=0.10, can the credit agency’s claim be supported?
Draw a data model for the following: A travel agency is frequently asked questions about tourist...
Draw a data model for the following: A travel agency is frequently asked questions about tourist destinations. For example, customers want to know details of the climate for a particular month, the population of the city, and other geographic facts. Sometimes they request the flying time and distance between two cities. The manager has asked you to create a database to maintain these facts.
What does Foot mean when she claims that the word good means the same thing when...
What does Foot mean when she claims that the word good means the same thing when applied to features of humans as when applied to features of plants?
d. A travel agency is frequently asked questions about tourist destinations. For example, customers want to...
d. A travel agency is frequently asked questions about tourist destinations. For example, customers want to know details of the climate for a particular month, the population of the city, and other geographic facts. Sometimes they request the flying time and distance between two cities. The manager has asked you to create a database to maintain these facts.
A pet association claims that the mean annual cost of food for dogs and cats are...
A pet association claims that the mean annual cost of food for dogs and cats are the same. The results for samples for the two types of pets are shown below. At alphaαequals=0.05 can you reject the pet​ association's claim? Assume the population variances are not equal. Assume the samples are random and​ independent, and the populations are normally distributed. Complete parts​ (a) through​ (e) below. Dogs Cats x overbar 1 equals= $ 202 x overbar 2 equals= $ 167...
A consumer advocate agency wants to find the mean repair cost of a washing machine. As...
A consumer advocate agency wants to find the mean repair cost of a washing machine. As part of the study 40 repair costs were selected and the mean repair cost was determined to be $150.00. From past studies the agency assumes that σ = $21. Construct a 90% confidence interval for the population mean. (Round confidence interval values to two decimal places.)
A shareholders’ group, in lodging a protest, claimed that the mean tenure for a chief executive...
A shareholders’ group, in lodging a protest, claimed that the mean tenure for a chief executive office (CEO) was at least nine years. A survey of 85 companies reported in The Wall Street Journal found a sample mean tenure of 7.27 years for CEOs with a standard deviation of 6.38 years (The Wall Street Journal, January 2, 2007). Compute the value of the test statistic. (Round to two decimal places) What is the p-value? (Round to three decimal places). At...
8. Research Question: A nutritionist claims that the mean daily consumption of fiber for 20-39-year-old males...
8. Research Question: A nutritionist claims that the mean daily consumption of fiber for 20-39-year-old males is less than 20 grams per day. (The National Cancer Institute recommends that individuals consume 20-30 grams of fiber per day) In a survey of 457 males who were 20-39 years old, conducted by the U.S. Department of Agriculture, it was found that the mean daily intake of fiber was 19.1 grams, with standard deviation of 9.1 grams. Decide whether there is enough evidence...
The daily demand for hotel rooms on Miami in Florida is given by the equation Qd=...
The daily demand for hotel rooms on Miami in Florida is given by the equation Qd= 150,000 – 275P. The daily supply of hotel rooms on Miami is given by the equation Qs= 25,000 +312.5P. Diagram these demand and supply curves in the price. What is the equilibrium price and quantity of hotel rooms on Miami?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT