In: Statistics and Probability
To the right are the outcomes that are possible when a couple has three children. Assume that boys and girls are equally likely, so that the eight simple events are equally likely. Find the probability that when a couple has three children, there is exactly 1 girl.
1st |
2nd |
3rd |
|
---|---|---|---|
boy |
boy |
boy |
|
boy |
boy |
girl |
|
boy |
girl |
boy |
|
boy |
girl |
girl |
|
girl |
boy |
boy |
|
girl |
boy |
girl |
|
girl |
girl |
boy |
|
girl |
girl |
girl |
Total number of outcomes = 8
Number of outcomes in which there is exactly 1 girl = 3
(boy boy girl, boy girl boy, girl boy boy)
P(when a couple has three chikdren, there is exactly 1 girl) = Number of outcomes in which there is exactly 1 girl / Total number of outcomes
= 3/8
= 0.375