Question

Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the likelihood that each baby will be a​ girl, but assume that the method has no​ effect, so the probability of a girl is 0.5. Assume that the groups consist of 41 couples. Complete parts​ (a) through​ (c) below. a. Find the mean and the standard deviation for the numbers of girls in groups of 41 births. The value of the mean is muequals nothing. ​(Type an integer or a decimal. Do not​ round.)

Answer 1

# Let X= number baby girls in 41 couples

n=41 p=0.5

#using Binomial Distribution for Which parameter

p=0.5 and n=41

therefore mean =np =41*0.5 =20.5

and standard deviation =(np(1-p))^1/2 =(41*0.5*(1-0.5))^1/2 =3.2016

#Mean=20.5 & standard deviation=3.2016