Question

In: Statistics and Probability

Over the past several months, an adult patient has been treated for tetany (severe muscle spasms)....

Over the past several months, an adult patient has been treated for tetany (severe muscle spasms). This condition is associated with an average total calcium level below 6 mg/dl. Recently, the patient's total calcium tests gave the following readings (in mg/dl). Assume that the population of x values has an approximately normal distribution. 9.9 8.6 10.5 8.9 9.4 9.8 10.0 9.9 11.2 12.1

a)Use a calculator with mean and sample standard deviation keys to find the sample mean reading x bar and the sample standard deviation s. (in mg/dl; round your answers to two decimal places.)

(b) Find a 99.9% confidence interval for the population mean of total calcium in this patient's blood. (in mg/dl; round your answer to two decimal places.)

lower limit

upper limit

(c) Based on your results in part (b), do you think this patient still has a calcium deficiency? Explain.

Yes. This confidence interval suggests that the patient may still have a calcium deficiency.

Yes. This confidence interval suggests that the patient no longer has a calcium deficiency.

No. This confidence interval suggests that the patient may still have a calcium deficiency.

No. This confidence interval suggests that the patient no longer has a calcium deficiency.

I have everything but the standard deviation s...and only a basic calculator

Solutions

Expert Solution

a)

Explanation: The mean and standard deviation are obtained in excel using the function =AVERAGE() and =STDEV(). The screenshot is shown below,

b)

The confidence interval for mean is obtained using the formula,

From the data values,

The t critical value is obtained from t distribution table for significance level = 0.001 and degree of freedom = n -1 = 10 - 1 = 9.

c)

Answer: No. This confidence interval suggests that the patient no longer has a calcium deficiency.

Explanation: Since the calcium deficiency level is less than the lower limit of the 99.9% confidence interval, we can say that patient no longer has a calcium deficiency.


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