Question

1. Using the values that you found in numbers 1 and 2, perform the following hypothesis test.
2. At a 10% significance level, test the claim that the women’s mean completion time is greater than ___________ (the men’s mean completion time).
3. 1. Ho: ___µ ≤ 27.914________   Ha: __µ > 27.914 (Claim)___ Label the claim. (6pts)
   2. What type of test will you use? (Z-Test, T-test, or 1-ProZTest) ______ (4 pts)
   3. Where is the rejection region? (Left-tailed, Right-tailed, Two-tailed test)
      (4 pts)
   4. Find the critical value(s). α = 0.10 ________________ (5 pts)
   5. What is the value of the standardized test statistic? _________________ (5 pts)
   6. What is your p-value? __________________ (5 pts)
   7. What is your decision? (Reject Ho or Fail to Reject Ho) _________________ (5 pts)
   8. Write your conclusion.
      There ____________ (is/is not) enough evidence to ______________ (support/reject) the claim that _________________. (6 points)

Mean Completion Times:

Men: 27.914 minutes

Women: 31.568 minutes

Sample Standard Deviation:

Men: 0.664

Women: 1.167

Sample Size:

Men: 32

Women: 35

Answer 1

27.914 minutes

a) testing

Ho : mu<=27.914 minutes vs Ha:m>27.914 minutes (right tailed test)

b) we use t test for testing the mean because population standard deviation is not given.

c)rejection region is on right tailed.

d) critical value of t at alpha=0.10 and df =n-1=34 (here n=35 number of females)

tcritical= 1.306951

e)under Ho:mu<=27.914 minutes

t=(Xbar-mu)/(S/sqrt(n)) ~ t(n-1) distribution

t=(31.568-27.914)/(1.167/sqrt(35))

t=3.654/0.1972

t=18.5294

f) Pvalue=P(t>=18.5294)<0.000001

g) as Pvalue <0.05 we reject Ho.

h) there is enough evidence to support the claim that women mean time is greater than mens.