In: Biology
Complete the table below as if you were going to use it as a study aid. Assume all values are per 1 molecule of glucose that begins the cellular respiration pathway.
Stage |
Location |
Start Molecule(s) |
End Molecule(s) |
ATP Produced |
ATP Used |
NADH Produced |
FADH2 Produced |
CO2 Produced |
Glycolysis Energy Investment |
Glucose |
|||||||
Glycolysis Energy Payoff |
2 G3P |
|||||||
Oxidation of Pyruvate |
||||||||
Citric Acid Cycle |
Mitochondria Matrix |
|||||||
Oxidative Phosphorylation |
10 NADP 2 FADH2 |
ATP O2 |
0 |
|||||
Total |
Glycolysis
In the investment phase where energy as ATP is put in, total of 2 ATP is used
In the payoff phase where net ATP and NADH molecules are created, a total of 4 ATP is made and 2 NADH.
Net production - 2 ATP and 2 NADH.
Oxidation of pyruvate
During conversion of pyruvate to acetyl CoA, each pyruvate molecule produce 1 NADH, loses one carbon atom with the release of carbon dioxide.
But 1 molecule of glucose produces 2 pyruvate.. so a total of 2 NADH and 2 CO2 produced here.
Citric acid cycle
1 molecule of glucose produces 2 pyruvate. So through two rounds of the citric acid cycle this generates 6 NADH, 2 FADH2, and 2 ATP. CO2 is produced in 2 steps. So a total of 4 CO2
Oxidative Phosphorylation
Oxidative phosphorylation is the process in which ATP is formed as a result of the transfer of electrons from NADH or FADH2 to O 2 by a series of electron carriers. Oxidative phosphorylation produces total of 34 ATP from 10 NADH and 2 FADH2. [ when 1 NADH produces 3 ATP and 1 FADH2. produces 2 ATP]
The final answer becomes :-
So 1 molecule of glucose that enters the cellular respiration pathway produces a total of 38 ATP molecules [40 - 2 used in glycolysis] , and 6 CO2