A 1.08×103-mg sample of impure potassium carbonate was titrated with 46.09 mL of 0.2770 M perchloric...

A 1.08×10³-mg sample of impure potassium carbonate was titrated with 46.09 mL of 0.2770 M perchloric acid. Calculate the percentage ofpotassium carbonate in the sample.

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81.522% pure potassium carbonate is present in the sample.

queen_honey_blossom answered 1 year ago

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