Question

In: Statistics and Probability

A quality survey asked recent customers of their experience at a local department store. One question...

  1. A quality survey asked recent customers of their experience at a local department store. One question asked for the customers rating on their service using categorical responses of average, outstanding, and exceptional. Another question asked for the applicant’s education level with categorical responses of Some HS, HS Grad, Some College, and College Grad. The sample data below are for 700 customers who recently visited the department store.

Education

Quality Rating

Some HS

HS Grad

Some College

College Grad

Average

55

80

50

35

Outstanding

60

105

65

70

Exceptional

35

65

35

45

Using a level of significance of 0.01, is there evidence to suggest that the customer’s Education level and Quality Rating are independent? In other words, is there a relationship or is there NO relationship between Education and Quality Rating?

  1. State the Null and Alternative hypothesis.

  1. What is the statistic you would use to analyze this?
  1. State your decision rule:

  1. Show your calculation:
  1. What is your conclusion?

Quality Rating and Education level are independent

OR

Quality Rating and Education level are NOT independent

Solutions

Expert Solution

Solution:

Here, we have to use chi square test for independence of two categorical variables.

Null hypothesis: H0: Two categorical variables the customer’s Education level and Quality Rating are independent.

Alternative hypothesis: Ha: Two categorical variables the customer’s Education level and Quality Rating are dependent.

We are given level of significance = α = 0.01

Test statistic formula is given as below:

Chi square = ∑[(O – E)^2/E]

Where, O is observed frequencies and E is expected frequencies.

E = row total * column total / Grand total

We are given

Number of rows = r = 3

Number of columns = c = 4

Degrees of freedom = df = (r – 1)*(c – 1) = 2*3 = 6

α = 0.05

Critical value = 16.81189

(by using Chi square table or excel)

Calculation tables for test statistic are given as below:

Observed Frequencies

Education

Quality Rating

Some HS

HS Grad

Some College

College Grad

Total

Average

55

80

50

35

220

Outstanding

60

105

65

70

300

Exceptional

35

65

35

45

180

Total

150

250

150

150

700

Expected Frequencies

Education

Quality Rating

Some HS

HS Grad

Some College

College Grad

Total

Average

47.14286

78.57143

47.14286

47.14286

220

Outstanding

64.28571

107.1429

64.28571

64.28571

300

Exceptional

38.57143

64.28571

38.57143

38.57143

180

Total

150

250

150

150

700

Calculations

(O - E)

7.857143

1.428571

2.857143

-12.1429

-4.28571

-2.14286

0.714286

5.714286

-3.57143

0.714286

-3.57143

6.428571

(O - E)^2/E

1.309524

0.025974

0.17316

3.127706

0.285714

0.042857

0.007937

0.507937

0.330688

0.007937

0.330688

1.071429

Test Statistic = Chi square = ∑[(O – E)^2/E] = 7.221549

χ2 statistic = 7.221549

P-value = 0.300844

(By using Chi square table or excel)

P-value > α = 0.01

So, we do not reject the null hypothesis

There is sufficient evidence to conclude that two categorical variables the customer’s Education level and Quality Rating are independent.

There is NO relationship between Education and Quality Rating.

Quality Rating and Education level are independent.


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