In: Math
Solve the following systems of equation using the formula by Cramer and with the inverse matrices.
4x1 - x2 + 2x3 = 8
-x1 + 2x2 = -7
x1 - 3x2 - 5x3 = 2
system Ax=b is
find determinant of A
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replace first column with vector b
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replace second column with vector b
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replace third column with vector b
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here matrix A is
4 | -1 | 2 |
-1 | 2 | 0 |
1 | -3 | -5 |
add the Identity Matrix to the right of our matrix
4 | -1 | 2 | 1 | 0 | 0 |
-1 | 2 | 0 | 0 | 1 | 0 |
1 | -3 | -5 | 0 | 0 | 1 |
by Gauss-Jordan Elimination
Divide row1 by 4
1 | -1/4 | 1/2 | 1/4 | 0 | 0 |
-1 | 2 | 0 | 0 | 1 | 0 |
1 | -3 | -5 | 0 | 0 | 1 |
Add (1 * row1) to row2
1 | -1/4 | 1/2 | 1/4 | 0 | 0 |
0 | 7/4 | 1/2 | 1/4 | 1 | 0 |
1 | -3 | -5 | 0 | 0 | 1 |
Add (-1 * row1) to row3
1 | -1/4 | 1/2 | 1/4 | 0 | 0 |
0 | 7/4 | 1/2 | 1/4 | 1 | 0 |
0 | -11/4 | -11/2 | -1/4 | 0 | 1 |
Divide row2 by 7/4
1 | -1/4 | 1/2 | 1/4 | 0 | 0 |
0 | 1 | 2/7 | 1/7 | 4/7 | 0 |
0 | -11/4 | -11/2 | -1/4 | 0 | 1 |
Add (11/4 * row2) to row3
1 | -1/4 | 1/2 | 1/4 | 0 | 0 |
0 | 1 | 2/7 | 1/7 | 4/7 | 0 |
0 | 0 | -33/7 | 1/7 | 11/7 | 1 |
Divide row3 by -33/7
1 | -1/4 | 1/2 | 1/4 | 0 | 0 |
0 | 1 | 2/7 | 1/7 | 4/7 | 0 |
0 | 0 | 1 | -1/33 | -1/3 | -7/33 |
Add (-2/7 * row3) to row2
1 | -1/4 | 1/2 | 1/4 | 0 | 0 |
0 | 1 | 0 | 5/33 | 2/3 | 2/33 |
0 | 0 | 1 | -1/33 | -1/3 | -7/33 |
Add (-1/2 * row3) to row1
1 | -1/4 | 0 | 35/132 | 1/6 | 7/66 |
0 | 1 | 0 | 5/33 | 2/3 | 2/33 |
0 | 0 | 1 | -1/33 | -1/3 | -7/33 |
Add (1/4 * row2) to row1
1 | 0 | 0 | 10/33 | 1/3 | 4/33 |
0 | 1 | 0 | 5/33 | 2/3 | 2/33 |
0 | 0 | 1 | -1/33 | -1/3 | -7/33 |
inverse matrix:
10/33 | 1/3 | 4/33 |
5/33 | 2/3 | 2/33 |
-1/33 | -1/3 | -7/33 |
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for system