Question

In: Statistics and Probability

Age Weight (pounds) 56 156 35 110 22 80 57 91 40 90 22 150 48...

Age Weight (pounds)
56 156
35 110
22 80
57 91
40 90
22 150
48 165
48 99
25 189
40 178
25 123
25 190
59 255
49 112
33 155
56 134
20 117
31 91
27 100
23 80
45 190
29 255
31 112
59 200
39 134
35 110
44 99
27 110
24 180
27 150

  

  1. The data represents the age and weight (in pounds) of 30 Langley residents.   Create a model to predict the expected weight of an individual based on their age. Maintain a minimum of 4 decimal places for intermediate calculations.   

a) What is the expected weight of an individual that is 27 years old?

b) How much variability in weight is accounted for by an individual’s age?  

c) How much variability in weight is accounted for by factors other than age?

d) Assume alpha is 0.05 Is an individual’s weight a significant predictor of an individual’s age? Provide the specific statistical evidence from your Excel output to support your answer.

Solutions

Expert Solution

(a) The model is:

Weight = 113.9148 + 0.7153*Age

The expected weight of an individual that is 27 years old is 133.228.

(b) 0.035

(c) 0.965

(d) The hypothesis being tested is:

H0: β1 = 0

H1: β1 ≠ 0

The p-value is 0.3189.

Since the p-value (0.3189) is greater than the significance level (0.05), we fail to reject the null hypothesis.

Therefore, we cannot conclude that an individual’s weight is a significant predictor of an individual’s age.

0.035
r   0.188
Std. Error   47.834
n   30
k   1
Dep. Var. Weight (pounds)
ANOVA table
Source SS   df   MS F p-value
Regression 2,355.8722 1   2,355.8722 1.03 .3189
Residual 64,066.2945 28   2,288.0819
Total 66,422.1667 29  
Regression output confidence interval
variables coefficients std. error    t (df=28) p-value 95% lower 95% upper
Intercept 113.9148
Age 0.7153 0.7049 1.015 .3189 -0.7287 2.1593
Predicted values for: Weight (pounds)
95% Confidence Interval 95% Prediction Interval
Age Predicted lower upper lower upper Leverage
27 133.228 110.508 155.949 32.645 233.811 0.054

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