In: Statistics and Probability
A local retailer claims that the mean waiting time is less than 8 minutes. A random sample of 20 waiting times has a mean of 6.3 minutes with a standard deviation of 2.1 minutes. At α = 0.01, test the retailerʹs claim. Assume the distribution is normally distributed. Use any method, however, follow the PHANTOMS acronym.
P - Parameter Statement
H - Hypotheses
A - Assumptions & Conditions
N - Name the Test and state the curve you're using
T - Test Statistic - Round your value to TWO decimals and state the command you used to find this value
O - Obtain the P-Value or Critical Value . State the command you are using to find these values
M - Make a Decision about the Null Hypothesis and explain why
S - State Your Conclusion About the Claim
Given:
Population mean(µ) = 8 minutes
Sample size(n) = 20
Sample mean(x bar) = 6.3 minutes
Sample standard deviation (s) = 2.1 minutes
α = 0.01
1) Parameter statement:
The claim statement is, "Mean waiting time is less than 8 minutes".
That is, the claim statement goes under the alternative hypothesis.
The population parameter is, µ.
Hence, alternative hypothesis H1: µ < 8.
2) Hypothesis
The null hypothesis and alternative hypothesis are opposite to each other.
Null hypothesis, H0: µ >= 8
And the alternative hypothesis is, H1: µ < 8
3) Assumtions and condition:
If the sample standard deviation is known, then we use T test.
If the population standard deviation is known, then we use Z test.
4) Test name: The alternative hypothesis is less than type.
Hence, the test is left tailed test.
Here, we are given the sample standard deviation.
Hence, we need to use 1 sample T test.
5) Test statistic:
Now, plug the values in the test statistic formula.
T = -3.62
That is, test statistic T = -3.62
Degrees of freedom = n-1 = 20 -1 = 19.
6) P-value:
Given: Significance level (α) = 0.01.
We need to find the p-value.
We can find out the p-value using technology or T table.
Suppose, we are using excel to find the p-value.
We can find out this by using the following excel command.
= T.DIST(Test statistic , Degrees of freedom, 1)
= T.DIST(-3.62 , 19, 1)
We will get, p-value = 0.000911
7) Make a decision:
The decision rule is,
If P-value > α, then we fail to reject the null hypothesis.
If P-value <= Test statistic, then we reject the null hypothesis.
p-value = 0.000911
α = 0.05
Here, P-value < α.
Hence, we reject the null hypothesis.
8) Conclusion about the claim:
Here, P-value < α.
Hence, we reject the null hypothesis.
Hence, we supports the claim statement.
That is, Mean waiting time is less than 8 minutes