In: Math
If the sum of first 6 terms is 9 times to the sum of first 3 terms of the same G.P., then common ratio of the series will be
Let a be the first term and r be the common ratio of the GP.
Sum of n terms of GP, Sn = a(r^(n)-1)/(r-1)
Given S6= 9S3
a(r⁶-1)/(r-1) = 9 a(r³-1)/(r-1)
(r⁶-1) = 9 (r³-1)
(r³-1)(r³+1) = 9(r³-1)
(r³+1) = 9
r³ = 8
r = 2
The common ratio of the series is r=2.