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Use the Student's t distribution to find tc for a 0.95 confidence level when the sample...

Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 21. (Round your answer to three decimal places.)

Use the Student's t distribution to find tc for a 0.99 confidence level when the sample is 14. (Round your answer to three decimal places.)

Use the Student's t distribution to find tc for a 0.90 confidence level when the sample is 18. (Round your answer to three decimal places.)

Solutions

Expert Solution

Solution :

Given that,

a) sample size = n = 21

Degrees of freedom = df = n - 1 = 21 - 1 = 20

At 95% confidence level

= 1 - 95%

=1 - 0.95 =0.05

/2 = 0.025

t/2,df = t0.025,20 = 2.086

b) sample size = n = 14

Degrees of freedom = df = n - 1 = 14 - 1 = 13

At 99% confidence level

= 1 - 99%

=1 - 0.99 =0.01

/2 = 0.005

t/2,df = t0.005,13 = 3.012

c) sample size = n = 18

Degrees of freedom = df = n - 1 = 18 - 1 = 17

At 90% confidence level

= 1 - 90%

=1 - 0.90 =0.10

/2 = 0.05

t/2,df = t0.05,17 = 1.740

orchestra answered 1 year ago
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