In: Statistics and Probability
Male and female students were asked to report how long they spend getting ready for a date:
Men: 28, 35, 52, 14
Female: 30,82,53,61
Conduct all steps of an independent samples t-test and report the result of your test
Given that,
Male and female students were asked to report how long they spend getting ready for a date.
Men/Male: 28, 35, 52, 14
Female: 30,82,53,61
Here we perfrom a independent samples t-test at 5% level of significance. [5% level of significance means ]
let, Xi = ith data of men students and Yi = ith data of Feamle students
Population mean for men students. and Population mean for female students.
Null and Alternative Hypothese:
vs
For this testing our appropriate test statistic is gievn by,
Where, Sample Mean for Men students , Sample Mean of for Female students ,
Number of observation for Men students, Number of observation for Female students ,
Sample Variance for Men students , Sample Varince for Female students ,
and under
Formula:
and [ Given ]
and
and
Table For Calculation:
28 | 30 | -4.25 | -26.5 | 18.0625 | 702.25 |
35 | 82 | 2.75 | 25.5 | 7.5625 | 650.25 |
52 | 53 | 19.75 | -3.5 | 390.0625 | 12.25 |
14 | 61 | -18.25 | 4.5 | 333.0625 | 20.25 |
Total=129 | Total=226 | Total=748.75 | Total=1385 |
Calculation: Putting the value from table and we get,
So value of test statistic is given by,
[ round to four decimal places ]
Rejection Rule:
We reject the null htpothesis at level if,
Here, and
[ from t-distribution probability table we get for DF=6 at level and for two tailed test t value is = 2.447 ]
i.e.
Decision/Result: Accept the null hypothesis at level
Coclusion: From the above result we can conclude that at 5% level of significance Men/Male and Female students are same for getting ready for a date.