Write the expression for K for the reaction below. Ag+(aq) + 2 NH3(aq) ⇄ Ag(NH3)2+(aq)

Write the expression for K for the reaction below.

Ag⁺(aq) + 2 NH₃(aq) ⇄ Ag(NH₃)₂⁺(aq)

Expert Solution

This is a reversible reaction

This is equation is of the form: aA + bB <----------> cC

For a reversible reaction at equilibrium: forward and reverse reactions are in balance

So, At equilibrium: rate_forward=rate_reverse

k_forward [A]^a[B]^b₌ k_backward [C]^c

where [A],[B],[C] are concentrations of A,B and C respectively and a,b,c are stoichiometric coefficients of A,B,C respectively. k_forward, k_backward are rate constants of forward and backward reactions respectively.

Applying this to the given equation,

k_forward [Ag⁺]¹[NH₃]²₌ k_backward [Ag(NH₃)₂]¹

k_forward / k_{backward =} [Ag(NH₃)₂]¹ /[Ag⁺]¹[NH₃]²

Write k = k_forward / k_backward

So, K = [Ag(NH₃)₂]¹ /[Ag⁺]¹[NH₃]²

So it can be generalised that k is the ratio of concentrations of products to reactants

queen_honey_blossom answered 2 years ago

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