Question

In: Statistics and Probability

Shirt Cost Basic T-Shirt (B) $18 New Arrival T-Shirt (N) $20 Premium T-Shirt (P) $22 Exclusive...

Shirt Cost
Basic T-Shirt (B) $18
New Arrival T-Shirt (N) $20
Premium T-Shirt (P) $22
Exclusive Playoffs T-Shirt (E) $24

Define the population as the four shirts and a sample of size two as the t-shirt that Josie chooses and the t-shirt that Will chooses.

  1. Identify the frequency distribution for the population

  2. Identify the frequency distribution for all combinations of sample means for Josie and Will choosing a shirt

  3. Verify that the population mean and mean of all possible sample means are equal

  4. Calculate the standard error of the mean

  5. Show your work using only numbers for each part (a-d) of the problem. Show all charts/tables. You do not need to enter the formulas or Greek letters.

Solutions

Expert Solution

Answer:

a) The frequency distribution for the population will be a uniform distribution. Here is what the table will look like:

Cost (in $) Shirt Probability
18 B 1/4
20 N 1/4
22 P 1/4
24 E 1/4

b) For the sample distribution, we have to consider each combination of shirts and take their average.

As Josie and Will both have 4 choices, there are 16 choices in all.

BB means that Josie and Will both choose Basic T-shirt. The average is $18.

BN means that Josie chose Basic T-shirt and Will both choose New Arrival T-shirt. The average is $19. Also, NB is a different combination with the same average of $19.

BP, NN, and PB all have the average of $20.

Using similar cases, we have:

Average Cost (in $) Shirts Probability
18 BB 1/16
19 BN, NB 2/16
20 BP, NN, PB 3/16
21 BE, NP. PN, EB 4/16
22 NE, PP, EN 3/16
23 PE, EP 2/16
24 EE 1/16

c) We write the population mean as sum of the product of the numbers and corresonding probability from the first table:

We write the sample mean as sum of the product of the numbers and corresonding probability from the second table:

So, the population mean of $21 is equal to the sample mean of $21. Hence, we have verified that the means are equal.

d) The population standard deviation is:

The sample standard deviation is:

The standard error of the mean is equal to the sample standard deviation = 1.6330.

NOTE:: * I HOPE YOUR HAPPY WITH MY ANSWER......**PLEASE SUPPORT ME WITH YOUR RATING

***PLEASE GIVE ME "LIKE"....ITS VERY IMPORTANT FOR ME NOW......PLEASE SUPPORT ME .......THANK YOU


Related Solutions

Data from three samples are shown below: A:        17        22        20        18     &n
Data from three samples are shown below: A:        17        22        20        18        23 B:        30        28        35        40        25 C:        44        39        54        21        52 Which sample has the largest relative dispersion? Justify your answer with relevant calculations. b. For each of the three samples listed, calculate the interquartile range (IQR). Which sample has the largest IQR?                    
Assume that ABC Co. sells T-shirts for $20/ shirt. The marginal cost of production is $9/...
Assume that ABC Co. sells T-shirts for $20/ shirt. The marginal cost of production is $9/ shirt, and fixed costs are $1,500/ year. The tax rate is 20%. What is the new break-even point of the number of T-shirts required to be sold if sales price and fixed costs are both reduced by 15%. Select one: a. None of the above b. 187 c. 159 Question 2 Question text XYZ Co. intends to expand operations and enters into a 10...
a) Given X ~N(10, 18)  and n = 64 P(13 < X < 14) = b) Given...
a) Given X ~N(10, 18)  and n = 64 P(13 < X < 14) = b) Given X ~N(10, 18)  and n = 64 x-bar ~ N(10, _________) c) Given X ~N(10, 18)  and n = 64 μ = _____
(a) Find ​P(T<1.321) when v=22. ​(b) Find ​P(T>2.069​) when v=23. ​(c) Find ​P(−2.145<T<2.997​) when v=14. ​(d)...
(a) Find ​P(T<1.321) when v=22. ​(b) Find ​P(T>2.069​) when v=23. ​(c) Find ​P(−2.145<T<2.997​) when v=14. ​(d) Find ​P(T>−2.998) when v=7.
1. Assume X ∼ N(20, 25), (a) find P(X > 25) (b) the value of x...
1. Assume X ∼ N(20, 25), (a) find P(X > 25) (b) the value of x if P(X > x) = 0.975. (c) find the values of a and b, two symmetrical values about 20 such that P(a < X < b) = 0.95. (d) If X1, X2, . . . , X100 is random sample for the distribution of X • what is the sampling distribution of the sample mean X¯? • find P(X >¯ 20.50) (e) Suppose the...
Using Table F, find the P-value interval for each test value. a. t = 3.025, n = 24, right-tailed b. t = - 1.145, n = 5, left-tailed c. t = 2.179, n = 13, two-tailed d. t = 0.665, n = 10, right-tailed
Using Table F, find the P-value interval for each test value.a. t = 3.025, n = 24, right-tailedb. t = - 1.145, n = 5, left-tailedc. t = 2.179, n = 13, two-tailedd. t =  0.665, n = 10, right-tailed
Find the​ 95% z-interval or​ t-interval for the indicated parameter. ​(a) μ     x̄=138​, s=38​, n=35 ​(b) p...
Find the​ 95% z-interval or​ t-interval for the indicated parameter. ​(a) μ     x̄=138​, s=38​, n=35 ​(b) p p̂=0.7​, n=73x ​(a) The​ 95% confidence interval for μ is ___ to ____. ​(Round to two decimal places as​ needed.)
Q1 a) Determine the first quartile Q1 for the binomial distribution: X~Bi(n=20,p=0.25) (see Lab 2). b)...
Q1 a) Determine the first quartile Q1 for the binomial distribution: X~Bi(n=20,p=0.25) (see Lab 2). b) Poisson distribution: X~Poisson(lambda=4.5). Evaluate Pr(X>5) and round to three decimal places. c) Assume that you need to construct a normal approximation to a Binomial distribution Binomial(n=200, p=0.45). What are the parameters of the corresponding normal distribution?
Suppose the demand for pizza in a small isolated town is p = 20 - 2Q. There are only two firms, A and B. Each has a cost function TC = 4 + 4Q.
Suppose the demand for pizza in a small isolated town is p = 20 - 2Q. There are only two firms, A and B. Each has a cost function TC = 4 + 4Q. Determine the equilibrium quantities of each if they form a cartel and share the market. Determine the equilibrium quantities of each if both behave as Cournot duopolists. Determine the equilibrium quantities of each if firm A is the Stackelberg leader.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT