Calculate the value at x = 1/5 for the particular solution y (x)
that meets the...
Calculate the value at x = 1/5 for the particular solution y (x)
that meets the initial conditions y (0) = 0 and y´ (0) = -1 of the
DE (use case 1): y´´ = 5 (y´) ^ 2
y"+y'-6y=1
1. general solution of corresponding homogenous equation
2. particular solution
3.solution of initial value problem with initial conditions
y(0)=y'(0)=0
Use variation of parameters to find a particular solution to the
variable coeff. differential equation:
y''+(2/x)y'+y=(1/x)
Also find a general solution to this equation.
y"-2y'+y=cos2t
1. general solution of corresponding homongenous equation
2. particular solution
3.solution of initial value problem with initial conditions
y(0)=y'(0)=0
Given that a particular solution of 2y′′ +3y′ +y = x^2 +7x+8 is
yp1=x^2+x+1 and that a particular solution of 2y′′ + 3y′ + y =
2sinx+4cosx is yp2=sinx-cosx, find a particular solution for 2y"
+3y' +y =3x^2 + 21x + 24 -sinx -2cosx
y"+y=cos(9t/10)
1. general solution of corresponding homongenous equation
2. particular solution
3.solution of initial value problem with initial conditions
y(0)=y'(0)=0
4. sketch solution in part 3
Obtain the general and particular solution of the DE
d2 y(x) / d x2 + (1/2) (dy(x) / dx) -
(1/2)y(x) = x + 1
By use of the variation of parameters method.
Evaluate all coefficients please.