Question
In: Statistics and Probability
Five males with an X-linked genetic disorder have one child each. The random variable x is...
Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder. Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviation. If a probability distribution is not given, identify the requirements that are not satisfied. x P(x) 0 0.027 1 0.149 2 0.324 3 0.324 4 0.149
Solutions
Expert Solution
Given probability distribution is valid if sum of probabilities equal to 1.
P(X) = 0.027 +
0.149 + 0.324 + 0.324 + 0.149 = 0.973
Since sum of probabilities not equal to 1 , this is not valid probability distribution.
orchestra answered 2 years agoRelated Solutions
Five males with an X-linked genetic disorder have one child each. The random variable x is...
Five males with an X-linked genetic disorder have one child
each. The random variable x is the number of children among the
five who inherit the X-linked genetic disorder. Determine whether
a probability distribution is given. If a probability distribution
is given, find its mean and standard deviation. If a probability
distribution is not given, identify the requirements that are not
satisfied.
x P(x)
0 0.029
1 0.164
2 0.307
3 0.307
4 0.164
5 0.029
Does the table show...
Five males with an X-linked genetic disorder have one child each. The random variable x is...
Five males with an X-linked genetic disorder have one child
each. The random variable x is the number of children among the
five who inherit the X-linked genetic disorder. Determine whether
a probability distribution is given. If a probability distribution
is given, find its mean and standard deviation. If a probability
distribution is not given, identify the requirements that are not
satisfied.
x
P(x)
0
0.0320.032
1
0.1630.163
2
0.3050.305
3
0.3050.305
4
0.1630.163
5
0.032
Five males with an X-linked genetic disorder have one child each. The random variable x is...
Five males with an X-linked genetic disorder have one child
each. The random variable x is the number of children among the
five who inherit the X-linked genetic disorder. Determine whether
a probability distribution is given. If a probability distribution
is given, find its (a) mean and (b) standard deviation. If a
probability distribution is not given, identify the requirements
that are not satisfied.
X | P(x)
0 | 0.033
1|0.156
2 | 0.311
3 | 0.311
4 | 0.156...
Five males with an X-linked genetic disorder have one child each. The random variable x is...
Five males with an X-linked genetic disorder have one child
each. The random variable x is the number of children among the
five who inherit the X-linked genetic disorder. Determine whether
a probability distribution is given. If a probability distribution
is given, find its mean and standard deviation. If a probability
distribution is not given, identify the requirements that are not
satisfied.
x P(x)
0 0.029
1 0.147
2 0.324
3 0.324
4 0.147
5 0.029
Five males with an X-linked genetic disorder have one child each. The random variable x is...
Five males with an X-linked genetic disorder have one child
each. The random variable x is the number of children among the
five who inherit the X-linked genetic disorder. Determine whether
a probability distribution is given. If a probability distribution
is given, find its mean and standard deviation. If a probability
distribution is not given, identify the requirements that are not
satisfied. x P(x) 0 0.034 1 0.153 2 0.313 3 0.313 4 0.153 5 0.034
Does the table show...
Five males with an X-linked genetic disorder have one child each. The random variable x is...
Five males with an X-linked genetic disorder have one child
each. The random variable x is the number of children among the
five who inherit the X-linked genetic disorder. Determine whether
a probability distribution is given. If a probability distribution
is given, find its mean and standard deviation. If a probability
distribution is not given, identify the requirements that are not
satisfied.
x
P(x)
0
0.0290.029
1
0.1610.161
2
0.3100.310
3
0.3100.310
4
0.1610.161
5
0.0290.029
Does the table show...
Five males with a particular genetic disorder have one child each. The random variable x is...
Five males with a particular genetic disorder have one child each.
The random variable x is the number of children among the five who
inherit the genetic disorder. Determine whether the table describes
a probability distribution. If it? does, find the mean and standard
deviation.
x
0
1
2
3
4
5
?P(x)
0.0008
0.0126
0.0798
0.2529
0.4003
0.2536
5.1.7 Question Help Five males with an X-linked genetic disorder have one child each. The random...
5.1.7 Question Help Five males with an X-linked genetic
disorder have one child each. The random variable x is the number
of children among the five who inherit the X-linked genetic
disorder. Determine whether a probability distribution is given. If
a probability distribution is given, find its mean and standard
deviation. If a probability distribution is not given, identify
the requirements that are not satisfied. x P(x) 0 0.028 0.028 1
0.153 0.153 2 0.319 0.319 3 0.319 0.319 4...
In a dominant x-linked genetic disorder, what sex could be affected? Explain in details your answer...
In a dominant x-linked genetic disorder, what sex could be
affected? Explain in details your answer citing all
possibilities.
1.Swyer syndrome is a Y-linked genetic disorder. What are the chances that any of their daughters...
1.Swyer syndrome is a Y-linked genetic disorder.
What are the chances that any of their daughters will have Swyer
syndrome? and What are the chances that any of their sons will have
it?
2.If a mutation causes a permanent change in the DNA sequence,
how is it that most mutations are “silent” mutations
3.Suppose a young woman is exposed to a chemical mutagen and
some permanent changes arise in the DNA (mutations) of some of her
germ line cells. Will...
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