Problem 5. (10 pts) In a differential amplifier, the non-inverting input is 3 cos (600t +...

Problem 5. (10 pts) In a differential amplifier, the non-inverting input is 3 cos (600t
+ 45◦) mV and the inverting input is 4cos (600t - 45◦) mV. The output is vo = 3cos (600t + 45◦) + 4.004cos (600t - 45◦) V. The CMRR is dB

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Manojponduru answered 1 year ago

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In a differential amplifier, the non-inverting input is 3 cos (600t + 45◦) mV and the...

In a differential amplifier, the non-inverting input is 3 cos (600t + 45◦) mV and the inverting input is 4cos (600t - 45◦) mV. The output is vo = 3cos (600t + 45◦) + 4.004cos (600t - 45◦) V. The CMRR is of ____ dB

In a differential amplifier, the noninverting input is 3cos(600t + 45°) mV and the inverting input...

In a differential amplifier, the noninverting input is 3cos(600t + 45°) mV and the inverting input is 4cos (600t - 45°) mV. The ooutput is vo = 3cos (600t - 45°) + 4.004cos (600t - 45°) V. The CMRR is of? The unit must be in dB. Is vo= 3cos(600t + 45 ◦ ) + 4.004cos(600t - 45◦) V instead of: vo = 3cos(600t - 45 ◦ ) + 4.004cos(600t - 45 ◦ ) V

In a differential amplifier, the noninverting input is 3 cos (600t + 45◦) mV and the...

In a differential amplifier, the noninverting input is 3 cos (600t + 45◦) mV and the inverting input is 4cos (600t - 45◦) mV. The output is vo = 3cos (600t + 45◦) + 4.004cos (600t - 45◦) V. The CMRR is_____ dB.

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