Question

Calculate the empirical forumla of your compound. Set the formula in the form Ni(Cl)x(NH3)y where x and y are determined from their titration results.

From my titration results:

% mass of Ni+2= 25.8% (0.192mmol)

% mass of Cl- = 26.8% (0.315mmol)

% mass of NH3 = 45.4% (1.12mmol)

Answer 1

Element     Mass        Moles                  ratio          smallest fraction

Ni                25.8       25.8/58.71 = 0.439 0.439/0.439 = 1                           1

Cl                26.8      26.8/35.5 = 0.755     0.755/0.439 = 1.72                       2

NH3            45.4     45.4/17 = 2.67           2.67/0.439 = 6.08                         6

Therefore, the emperical formula is: [Ni(NH3)6]Cl2