Question

In: Chemistry

Two 20.0g ice cubes at -15.0C re placed into 255g of water at 25.0C. a.) Calculate...

Two 20.0g ice cubes at -15.0C re placed into 255g of water at 25.0C.

a.) Calculate the amount of heat required to heat to and completely melt the ice at the melting point.

b.) If that heat came from the water, what temperature would the liwuid water drop to in melting ice?

c.) What would the final temperature be when the water from the melted ice reached therma equilibrium with water originally in the glass?

Expert Solution

a)

heat required to melt ice:

Qtotal = Qsensible + Qlatent

Qtotal = m*C*(Tf-Ti) + Qlatent

Qtotal = 2*20*(2.01)(0 - -15) + 2*20*334 = 14566 J required to melt

b)

find water temperature:

Qwater = m*C*(Tf-Ti)

-14566 = 255*4.184*(Tf-25)

Tf = -14566 / 255 / 4.184 + 25 = 11.35 °C

c)

find final T if melt water reaches equilibrium

Qwater hot = -Qwater cold

Qwater hot = m*C*(Tf-Ti) = 255*4.184*(Tf-11.35 )

Qwater cold = m*C*(TF-Ti) = 2*20*4.184*(Tf-0)

255*4.184*(Tf-11.35 ) = - 2*20*4.184*(Tf-0)

1066.92Tf -11.35*1066.92 = -167.36*Tf

Tf(1066.92 + 167.36) = 12109.542

Tf = 12109.542 / (1066.92 + 167.36)

Tf = 9.8110 °C

queen_honey_blossom answered 2 years ago

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