Question

Data

Current	New
377	312
266	313
314	264
323	289
305	299
344	354
304	246
290	269
276	327
331	219
382	248
321	291
309	333
321	382
291	290
341	236
340	269
354	349
375	308
378	362
256	315
404	277
	301
	318
	322

1.

A) What is the mean amount of time required to finish the procedure using the CURRENT process?  (Round to the nearest TENTH of a second)

B) What is the mean amount of time required to finish the procedure using the NEW process? (Round to the nearest TENTH of a second)

C) What is the standard deviation for the amount of time required to finish the procedure using the CURRENT process?

(Round to the nearest tenth of a second)

D) What is the standard deviation for the amount of time required to finish the procedure using the NEW process?

(Round to the nearest tenth of a second)

E) Now run the appropriate test.  (Round to FOUR places)

F) Report the appropriate p-value: (Round to FOUR places)

Answer 1

Solution-A:

mean=sum of values/total

=8143/25

=325.72

=325.7

(ronded to nearest tenth)

mean amount of time required to finish the procedure using the CURRENT process=325.7

Solution-b:

mean=sum of values/total

=6552/22

=297.818

=297.8

mean amount of time required to finish the procedure using the NEW process=297.8

C) What is the standard deviation for the amount of time required to finish the procedure using the CURRENT process

standard deviation for the amount of time required to finish the procedure using the CURRENT process

s=37.7

Solution-d:

standard deviation for the amount of time required to finish the procedure using the NEW process

42.8 seconds