The following summary statistics were derived from a simple random sample: Mean=63.7 Standard deviation=14.1 n=51 Compute...

The following summary statistics were derived from a simple random sample:

Mean=63.7

Standard deviation=14.1

n=51

Compute a 99% confidence interval for the population mean. Report the upper limit for your answer.

Solutions

Expert Solution

Solution :

Given that,

Point estimate = sample mean = = 63.7

sample standard deviation = s = 14.1

sample size = n = 51

Degrees of freedom = df = n - 1 = 51 - 1 = 50

At 99% confidence level the t is ,

= 1 - 99% = 1 - 0.99 = 0.01

t,df = t0.01,50 = 2.403

Margin of error = E = t,df * (s / $\sqrt$ n)

= 2.403 * (14.1 / $\sqrt$ 51)

Margin of error = E = 4.7

At 99% upper confidance level is

+ E

63.7 + 4.7

68.4

The upper limit : 68.4

orchestra answered 1 year ago

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