Problem 3: The carrier c(t) = 100cos(2p fct) is frequency modulated by the signal m(t) =...

Problem 3: The carrier c(t) = 100cos(2p fct) is frequency modulated by the signal m(t) =
5cos(20000pt) , where fc = 108 Hz. The peak frequency deviation is 20 kHz. Determine the
amplitude and frequency of all the signal components that have a power level of at least 10% of
the power of the un-modulated carrier component.
Hint: The wide-band FM has frequency components, fc, fc+ fm, fc? fm, fc+2 fm, fc?2 fm,
and so on. The amplitude of the frequency components fc+n fm and fc?n fm is AcJn(b) where the
symbols have common meaning. You need to the find the frequency and amplitude of the components
that have at least 10% of the power of the un-modulated carrier (i.e., the signal components
that have at least 500 Watt power).

Solutions

Expert Solution

Manojponduru answered 1 year ago

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