In: Statistics and Probability
12. A sample of 7 repair costs for smart phones have an average of $95.56 and a standard deviation of $20. Build the 90% confidence interval for the true average cost to repair a smart phone.
)Given that,
= 95.56
s =20
n = 7
Degrees of freedom = df = n - 1 =7 - 1 = 6
At 90% confidence level the t is ,
= 1 - 90% = 1 - 0.90 = 0.1
/ 2 = 0.1 / 2 = 0.05
t /2,df = t0.05,6= 1.943 ( using student t table)
Margin of error = E = t/2,df * (s /n)
= 1.943 * (20 / 7) = 14.7
The 90% confidence interval is,
- E < < + E
95.56 - 14.7 < < 95.56 + 14.7
80.86< < 110.26