About 63% of the residents in a town are in favor of building a new high...

About 63% of the residents in a town are in favor of building a new high school. 105 residents

are randomly selected. What is the probability that the sample proportion in favor of building a

new school is less than 55%?

Solutions

Expert Solution

Solution

Given that,

p = 63%=0.63

1 - p = 1-0.63=0.37

n = 105

= p =0.63

= $\sqrt$ [p ( 1 - p ) / n] = $\sqrt$ [(0.63*0.37) / 105 ] = 0.047

P( < 0.55) =

= P[( - ) / < (0.55-0.43) /0.047 ]

= P(z <2.55 )

Using z table,

=0.9946

probability=0.9946

orchestra answered 1 year ago

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