In: Statistics and Probability
About 63% of the residents in a town are in favor of building a new high school. 105 residents
are randomly selected. What is the probability that the sample proportion in favor of building a
new school is less than 55%?
Solution
Given that,
p = 63%=0.63
1 - p = 1-0.63=0.37
n = 105
= p =0.63
= [p ( 1 - p ) / n] = [(0.63*0.37) / 105 ] = 0.047
P( < 0.55) =
= P[( - ) / < (0.55-0.43) /0.047 ]
= P(z <2.55 )
Using z table,
=0.9946
probability=0.9946