In: Chemistry
you have a stock solution of 300ppm of analyte under investigation. how much of that stock solution in mL do you need to prepare V2=247.2 mL of M2=143.3 ppm solution?
Formula for dilution :
M1 V1 = M2V2
Concentration stock solution M1 = 300ppm
Volume of stock solution V1 = ? ( to be found)
Concentration of final solution M2 = 143.3ppm
Volume of the final solution V2 = 247.2mL
300ppm x V1 = 143.3ppm x 247.2mL
Let us divide both sides by 300ppm
The volume of stock solution needed to prepare 247.2mL of 143.3ppm solution is
118.1mL