In: Chemistry
Candy chemist was asked to determine the concentration (m/m) of new alcoholic beverage from the molarity, which was determined to be 3.205 M and the density, which was found to be .984 g/mL/ What is the mass percent of ethanol (MM= 46.068 / mol) in the beverage ?
Molarity= { [(w/W)%] X10Xd} x[1/M.wt]
Molarity= 3.205 denisity= 0.984 M.wt= 46.08
Molarity= { [(w/W)%] X10Xd} x[1/M.wt]
3.025 = { [(w/W)%] x10x0.984x[1/46.08]
w/W%= [3.025x46.08]/[9.84]
w/W%= [139.39]/[9.84]
=14.165%