In: Mechanical Engineering
(A) Reynold's number , Re= UL/v
U= Speed of car in m/s = 95*0.27778 = 26.3891 m/s
L = length of the car = 6 m
v = kinematic viscosity of air = 1.5 * 10-5 m2/s
Re = 26.3891/ v = 1.759273 * 106
(B) lift to drag ratio = 3: 1 ( means every 3 miles it travels forward losses an altitude of 1 mile)
1 mile = 1.60934 Km
distance to airport = 106km
current altitude = 17.500 Km
Based on the ratio given, the flight need 21.955 times to loss its altitude for travelling to 106 Km. But at 10.8 altitude will become 0.
flight will glide until 53.856 Km, then it will loss the altitude completely