(A) car has a length of 6m and is travelling at speed of 95km/hr. What is...

(A) car has a length of 6m and is travelling at speed of 95km/hr. What is its Reynolds number?(5s.f , tolerance +/-500)

(B) for Concorde SST plane, how far could it actually glide in km?(3s.f), (has lift/drag ratio of 6:2, engines failed at altitude of 17500m and can make it to airport 106km away)

Solutions

Expert Solution

(A) Reynold's number , R_e= UL/v

U= Speed of car in m/s = 95*0.27778 = 26.3891 m/s

L = length of the car = 6 m

v = kinematic viscosity of air = 1.5 * 10^-5 m²/s

R_e = 26.3891/ v = 1.759273 * 10⁶

(B) lift to drag ratio = 3: 1 ( means every 3 miles it travels forward losses an altitude of 1 mile)

1 mile = 1.60934 Km

distance to airport = 106km

current altitude = 17.500 Km

Based on the ratio given, the flight need 21.955 times to loss its altitude for travelling to 106 Km. But at 10.8 altitude will become 0.

flight will glide until 53.856 Km, then it will loss the altitude completely

samet mamat answered 2 years ago

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