Question
In: Statistics and Probability
Exhibit 11-5 The table below gives beverage preferences for random samples of teens and adults. Beverage ...
Exhibit 11-5
The table below gives beverage preferences for random samples of teens and adults.
Beverage Teens Adults Total
Coffee 50 200 250
Tea 100 150 250
Soft Drink 200 200 400
Other 25 75 100
Total 375 625 1,000
We are asked to test for independence between age (i.e., adult and teen) and drink preferences.
Refer to Exhibit 11-5. The calculated value for this test for independence is
show will excel
Question options:
8.40
66.67
82.50
Solutions
Expert Solution
The null and alternative hypothesis for this Chi-square test of independence is:
The Age and
the drink preference for teen and adults is independent.
The Age and
the drink preference for teen and adults is not independent or it
is dependent.
The test-statistic is given as: 
; with degrees of freedom, df=(r-1)(c-1)
where, r: number of rows , c: number of columns
We have given the observed data for the 1000 random sample of teen and adults and their drink preference.
Observed frequency:
| Teen | Adult | Total | |
| Coffee | 50 | 200 | 250 |
| Tea | 100 | 150 | 250 |
| Soft Drink | 200 | 200 | 400 |
| Other | 25 | 75 | 100 |
| Total | 375 | 625 | 1000 |
Now the Expected frequency is calculated as:
Expected frequency:
| Teen | Adult | |
| Coffee |  |
 |
| Tea | |
|
| Soft Drink |  |
 |
| Other |  |
 |
The Chi-square statistic is calculated as 
orchestra answered 1 year agoRelated Solutions
The table below gives beverage preferences for random samples of teens and adults. Beverage Teens Adults...
The table below gives beverage preferences for random samples of
teens and adults.
Beverage
Teens
Adults
Total
Coffee
50
200
250
Tea
100
150
250
Soft Drink
200
200
400
Other
25
75
100
Total
375
625
1,000
We are asked to test for independence between age (i.e., adult
and teen) and drink preferences.
Refer to Exhibit 11-5. The result of the test is that the
Question 11 options:
hypothesis of independence can be rejected
hypothesis of independence cannot...
The table below gives beverage preferences for random samples of teens and adults. teens adults...
The table below gives beverage preferences for random samples of teens and adults.
teens
adults
total
coffee
50
200
250
tea
100
150
250
soft drinks
200
200
400
other
50
50
100
400
600
1000
a. We are asked to test for independence between age (i.e., adult and teen) and drink preferences. With a .05 level of significance, the critical value for the test is?
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b. The expected number...
The table below gives beverage preferences for random samples of teens and adults. Teens Adults Total...
The table below gives beverage preferences for random samples of
teens and adults. Teens Adults Total Coffee 50 200 250 Tea 100 150
250 Soft Drink 200 200 400 Other 50 50 100 400 600 1000 We are
asked to test for independence between age (i.e., adult and teen)
and drink preferences. With a .05 level of significance, a. state
the hypothesis b. Calculate the expected frequencies c. what are
the degrees of freedom d. what is the critical value...
The table below gives beverage preferences for random samples of teens and adults. Teens Adults Total...
The table below gives beverage preferences for random samples of
teens and adults.
Teens
Adults
Total
Coffee
50
200
250
Tea
100
150
250
Soft Drink
200
200
400
Other
50
50
100
400
600
1,000
We are asked to test for independence between age (i.e., adult and
teen) and drink preferences. If the value of the test statistic is
greater than the critical value of the test statistic, what is the
result of the test?
Select one:
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The table below shows pulse rates taken from random samples of
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Use one-way analysis of variance (ANOVA) to test the claim that the
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The two data sets in the table below are dependent random samples. The population of (...
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112
130
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140
142
146
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A) Plot systolic blood pressure side-by-side boxplot for teen
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