In: Finance
Consider a two-period binomial model with u=1.2 and d=0.85. What is the current equilibrium price of a call with a strike price of $20.00, if shares of stock are currently trading at $20, and the one-period risk free rate is 4%?
| S0 = | Stock price today | = | 20 | |
| r= | risk free interest rate | = | 4% | |
| u= | up factor | = | 1.2 | |
| d= | Down factor | = | 0.85 | |
| X = | Exercise price | = | 20 | |
| We first compute the possible values of the stock at each node in the binomial tree: | ||||
| t=1 | ||||
| S+ = | = 20*1.2 | = | 24 | |
| S- = | = 20*0.85 | = | 17 | |
| t = 2 = T | ||||
| S++ = | = 20*1.2*1.2 | = | 28.8 | |
| S+ - = | = 20*1.2*0.85 | = | 20.4 | |
| S- - = | = 20*0.85*0.85 | = | 14.45 | |
| Intrinsic value of the call option at expiration | ||||
| c++ = | = Max(0, S++ - X) | |||
| = Max(0, 28.8 - 20) | = | 8.8 | ||
| c+ - = | = Max(0, S+ - - X) | |||
| = Max(0, 20.4 - 20) | = | 0.4 | ||
| c- - = | = Max(0, S- - - X) | |||
| = Max(0, 14.45 - 20) | = | 0 | ||
| ∏= | Risk neutral probability | = | (1+r-d)/(u-d) | |
| ∏= | Risk neutral probability | = | (1+0.04-0.85)/(1.2-0.85) | |
| = | 0.5429 | |||
| 1- ∏= | = | 0.4571 | ||
| Compute the value of call option at each node for t=1 | ||||
| c+ = | Call price t=1 | = | [∏c++ + (1-∏)c+ - ]/ (1+r) | |
| c+= | [0.5429*8.8 + 0.4571*0.399999999999999] /[1+0.04 ] | = | 4.77 | |
| c- = | Call price t=1 | = | [∏c+ - + (1-∏)c- - ]/ (1+r) | |
| [0.5429*0.399999999999999 + 0.4571*0] /[1+0.04 ] | = | 0.21 | ||
| Finally, value of call option | ||||
| c = | Call price t=0 | = | [∏c+ + (1-∏)c - ]/ (1+r) | |
| c = | Call price today | |||
| [0.5429*4.77 + 0.4571*0.21] /[1+0.04 ] | = | 2.58 | 
Call price is 2.58