In: Statistics and Probability
Consider the drawing of a probability tree for this data. What are the prior probabilities that would be on the tree and what would they be for?
WOMEN EYE COLOR CHILDREN
18 Brown No
22 Brown Yes
09 Blue No
21 Blue Yes
12 Green No
18 Green Yes
MEN EYE COLOR CHILDREN
24 Brown No
16 Brown Yes
12 Blue No
18 Blue Yes
10 Green No
20 Green Yes
Let W and M denote the event of the person being a Woman and Man respectively. Let Br, Bl, G denote the event that the eye colour is Brown, Blue and Green respectively. Let C and A denote the event that the person selected is a Child and Adult respectively.
Based on the given data, by definition of probability,
Probability of occurrence of an event = No. of favorable cases / Total No. of cases
P(W) = P(M) = 100 /200 = 0.5
P(Br) = (18+22+24+16) / 200 = 80 / 200 = 0.40
P(Bl) = (09+21+12+18) / 200 = 60 / 200 = 0.30
P(G) = (12+18+10+20) / 200 = 60 / 200 = 0.30
P(C) = (22+21+18+ 16+18+20) / 200 = 115 / 200 = 0.575
P(A) = (18 + 9 +12+ 24+12+10) / 200 = 85 / 200 = 0.425
P(WC) = (22 + 21 + 18) / 200 = 61 = 200 = 0.305
P(WA) = (18 + 9 + 12) / 200 = 39 / 200 = 0.195
P(MC) = (16 + 18 + 20) / 200 = 0.27
P(MA) = (24 + 12 + 10) / 200 = 0.23
P(WCBr) = 22 /200 = 0.11
P(WCBl) = 21 / 200 = 0.105
P(WCG) = 18 / 200 = 0.09
P(WABr) = 18 /200 = 0.09
P(WABl) = 09 / 200 = 0.045
P(WAG) = 12 / 200 = 0.06
P(MCBr) = 16 /200 = 0.08
P(MCBl) = 18 / 200 = 0.09
P(MCG) = 20 / 200 = 0.10
P(MABr) = 24 / 200 = 0.12
P(MABl) = 12 / 200 = 0.06
P(MAG) = 10 / 200 = 0.05
Tree Diagram: