In: Statistics and Probability
In a research conducted on a sample of size 20, the mean and standard deviation obtained are 88.4 and 28.97. Assuming that the population distribution follows normality, find a 99% confidence interval for the true mean.
What is the sample mean value?
Which distribution is used in this case?
What is the Maximal Margin of Error?
What is the confidence interval?
Sample mean = 88.4
t distribution
Margin of error = 18.533
CI = (69.867, 106.933)
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