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 f   is a twice differentiable function and that itssecond partial derivatives are continuous.Let  h(t)...

f   is a twice differentiable function and that its second partial derivatives are continuous.
Let  h(t) = f (x(t), y(t))  where  x = 2et  and  y = t.
Suppose that  fx(2, 0) = 3,  fy(2, 0) = 2,  fxx(2, 0) = 4,  fyy(2, 0) = 3,  and  fxy(2, 0) = 1.

h'(t) = fx * 2et+ fy

find h''(t) when t = 0.

(I don't understand how for the second partial derivative d/dy (fy) = d/dt (x) *fyx + d/dt(y) * fyy

Could you explain this step for me in the solution. Thank you :)

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