In: Statistics and Probability
Heavy football players: Following are the weights, in pounds, for samples of offensive and defensive linemen on a professional football team at the beginning of a recent year.
| Offense: | 
 289  | 
 337  | 
 275  | 
 269  | 
 263  | 
 291  | 
 321  | 
 352  | 
 279  | 
 270  | 
 269  | 
 302  | 
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Defense: | 
 250  | 
 290  | 
 273  | 
 355  | 
 275  | 
 320  | 
 320  | 
 333  | 
 360  | 
 345  | 
 259  | 
 334  | 
(a) Find the sample standard deviation for the weights for the offensive linemen. Round the answer to at least one decimal place.
| The sample standard deviation for
the weights for the offensive linemen is
 lb . | 
(b) Find the sample standard deviation for the weights for the defensive linemen. Round the answer to at least one decimal place.
| The sample standard deviation for
the weights for the defensive linemen is
 lb . | 
a.
given data,
Offense:  
289 337 275 269 263 291 321 352 279 270 269 302
Defense:  
250 290 273 355 275 320 320 333 360 345 259 334
Mean = Sum of observations/ Count of observations
Mean = (289 + 337 + 275 + 269 + 263 + 291 + 321 + 352 + 279 + 270 +
269 + 302 / 12) = 293.0833
Variance
Step 1: Add them up
289 + 337 + 275 + 269 + 263 + 291 + 321 + 352 + 279 + 270 + 269 +
302 = 3517
Step 2: Square your answer
3517*3517 =12369289
…and divide by the number of items. We have 12 items , 12369289/12
= 1030774.0833
Set this number aside for a moment.
Step 3: Take your set of original numbers from Step 1, and square
them individually this time
289^2 + 337^2 + 275^2 + 269^2 + 263^2 + 291^2 + 321^2 + 352^2 +
279^2 + 270^2 + 269^2 + 302^2 = 1040177
Step 4: Subtract the amount in Step 2 from the amount in Step
3
1040177 - 1030774.0833 = 9402.9167
Step 5: Subtract 1 from the number of items in your data set, 12 -
1 = 11
Step 6: Divide the number in Step 4 by the number in Step 5. This
gives you the variance
9402.9167 / 11 = 854.8106
Step 7: Take the square root of your answer from Step 6. This gives
you the standard deviation
29.2371
b.
Mean = Sum of observations/ Count of observations
Mean = (250 + 290 + 273 + 355 + 275 + 320 + 320 + 333 + 360 + 345 +
259 + 334 / 12) = 309.5
Variance
Step 1: Add them up
250 + 290 + 273 + 355 + 275 + 320 + 320 + 333 + 360 + 345 + 259 +
334 = 3714
Step 2: Square your answer
3714*3714 =13793796
…and divide by the number of items. We have 12 items , 13793796/12
= 1149483
Set this number aside for a moment.
Step 3: Take your set of original numbers from Step 1, and square
them individually this time
250^2 + 290^2 + 273^2 + 355^2 + 275^2 + 320^2 + 320^2 + 333^2 +
360^2 + 345^2 + 259^2 + 334^2 = 1165730
Step 4: Subtract the amount in Step 2 from the amount in Step
3
1165730 - 1149483 = 16247
Step 5: Subtract 1 from the number of items in your data set, 12 -
1 = 11
Step 6: Divide the number in Step 4 by the number in Step 5. This
gives you the variance
16247 / 11 = 1477
Step 7: Take the square root of your answer from Step 6. This gives
you the standard deviation
38.4318
Answer:
a.
the sample standard deviation for the weights for the offensive
linemen =29.2371
b.
the sample standard deviation for the weights for the defensive
linemen =38.4318