In: Statistics and Probability
solution
Solution :
Given that,
sample mean = = 9.41
sample standard deviation = s = 1.38
sample size = n = 35
Degrees of freedom = df = n - 1 = 35 - 1= 34
At 99% confidence level
= 1 - 99%
=1 - 0.99 =0.01
/2
= 0.005
t/2,df
= t0.005,34 = 2.728
Margin of error = E = t/2,df * (s /n)
= 2.728* ( 1.38/ 35)
Margin of error = E =0.6363
The 99% confidence interval estimate of the population mean is,
- E < < + E
9.41 - 0.6363 < < 9.41 + 0.6363
8.7737 < < 10.0463
(8.7737 , 10.0463)
The 99% confidence interval estimate of the population mean is fall between lower bound and upper bound (8.7737 , 10.0463)