In: Statistics and Probability
Suppose you wish to test a hypothesis that two treatments, A and B, are equivalent against the alternative that the responses for A tend to be larger than those for B.
a. If the number of pairs equals 32, give the rejection region for the large-sample Wilcoxon signed rank test for alpha equals α=0.10.
b. Suppose that Upper T Subscript plusT+equals=404. State your test conclusions.
c. Find the p-value for the test and interpret it.
z value obtained from the above critical values
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T+ equals = 273 State Test conclusion + = 243; 0: 3%, Null hypothesis & Two treatments Ä & are equivalent Alternatve hypothesir: Responses for å tend to be larger than those for 'B' Z = Tt- en (n+1)) 4 nenti) (90+1) 32-(32+1) (2132)+1) Qy 24 42- 32 ( 32+1) 404-264 2-61785. 68 640 24 the Z calculated 2.61785 > Z critical 1.28 value 2.61785 7 1.28
So, we Reject the null hypothesis & accept the alternative hypothesis, & we conclude that Responses for 'A' tend to be larger than those for B (2 P-value Plz>z] =P(Z > 2.61755] <!-p (za 2661785] -1- 0.9955 0.0045 (since p-value < 0.05) 0.0045 We Reject null hy pothesis & accept alternative hypothesiss ('A' tend to be larger than those for B)